In this chapter, we provide RD Sharma Class 7 ex 17.5 Solutions Chapter 17 Constructions for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 7 ex 17.5 Solutions Chapter 17 Constructions Maths pdf, Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 7 |

Subject | Maths |

Chapter | Chapter 17 |

Chapter Name | Constructions |

Exercise | Ex 17.5 |

**RD Sharma Solutions for Class 7 Chapter 17 Constructions** **Ex 17.5 Download PDF**

**Constructions Exercise 17.5**

**Question: 1**

Draw a right triangle with hypotenuse of length 5 cm and one side of length 4 cm.

**Solution:**

**Steps of construction:**

- Draw a line segment QR = 4 cm.
- Draw ∠
*QRX*of measure 90°. - With centre Q and radius PQ = 5 cm, draw an arc of the circle to intersect ray RX at P.
- Join PQ to obtain the desired triangle PQR.

PQR is the required triangle.

**Question: 2**

Draw a right triangle whose hypotenuse is of length 4 cm and one side is of length 2.5 cm.

**Solution:**

**Steps of construction:**

- Draw a line segment QR = 2.5 cm.
- Draw ∠
*QRX*of measure 90°. - With centre Q and radius PQ = 4 cm, draw an arc of the circle to intersect ray RX at P.
- Join PQ to obtain the desired triangle PQR.

PQR is the required triangle.

**Question: 3**

Draw a right triangle having hypotenuse of length 5.4 cm, and one of the acute angles of measure 30°

**Solution:**

Let ABC be the right triangle at A such that hypotenuse BC = 5.4 cm. Let cC = 30°.

Therefore ∠*A *+ ∠*B *+ ∠*C *= 180°∠*B *= 180°− 30°− 90° = 60°

**Steps of construction:**

- Draw a line segment BC = 5.4 cm.
- Draw angle CBY = 60°
- Draw angle BCX of measure 30° with X on the same side of BC as Y.
- Let BY and CX intersect at A.

Then ABC is the required triangle.

**Question: 4**

Construct a right triangle ABC in which AB = 5.8 cm, BC = 4.5 cm and ∠*C *= 90°.

**Solution:**

**Steps of construction:**

- Draw a line segment BC = 4.5 cm.
- Draw ∠
*BCX*of measure 90°.. - With centre B and radius AB = 5.8 cm, draw an arc of the circle to intersect ray BX at A.
- Join AB to obtain the desired triangle ABC.

ABC is the required triangle.

**Question: 5**

Construct a right triangle, right angled at C in which AB = 5.2 cm and BC= 4.6 cm.

**Solution:**

**Steps of construction:**

- Draw a line segment BC = 4.6 cm.
- Draw ∠
*BCX*of measure 90° - With centre B and radius AB = 5.2 cm, draw an arc of the circle to intersect ray CX at A.
- Join AB to obtain the desired triangle ABC.

ABC is the required triangle.

**All Chapter RD Sharma Solutions For Class 7 Maths**

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