In this chapter, we provide RD Sharma Class 7 ex 17.3 Solutions Chapter 17 Constructions for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 7 ex 17.3 Solutions Chapter 17 Constructions Maths pdf, Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 7 |

Subject | Maths |

Chapter | Chapter 17 |

Chapter Name | Constructions |

Exercise | Ex 17.3 |

**RD Sharma Solutions for Class 7 Chapter 17 Constructions** **Ex 17.3 Download PDF**

**Constructions Exercise 17.3**

**Question: 1**

Draw △*ABC* in which AB = 3 cm, BC = 5 cm and ∠*Q *= 70°.

**Solution:**

**Steps of construction:**

- Draw a line segment AB of length 3 cm.
- Draw ∠
*XBA*=70°. - Cut an arc on BX at a distance of 5 cm at C.
- Join AC to get the required triangle.

**Question: 2**

Draw △*ABC* in which ∠*A*=70°., AB = 4 cm and AC= 6 cm. Measure BC.

**Solution:**

**Steps of construction:**

- Draw a line segment AC of length 6 cm.
- Draw ∠
*XAC*=70°. - Cut an arc on AX at a distance of 4 cm at B.
- Join BC to get the desired triangle.
- We see that BC = 6 cm.

**Question: 3**

Draw an isosceles triangle in which each of the equal sides is of length 3 cm and the angle between them is 45°.

**Solution:**

**Steps of construction:**

Draw a line segment PQ of length 3 cm.

Draw ∠*QPX*=45°.

Cut an arc on PX at a distance of 3 cm at R.

Join QR to get the required triangle.

**Question: 4**

Draw △*ABC* in which ∠*A *= 120°, AB = AC = 3 cm. Measure ∠*B* and ∠*C*.

**Solution:**

**Steps of construction:**

- Draw a line segment AC of length 3 cm.
- Draw ∠
*XAC*= 120°. - Cut an arc on AX at a distance of 3 cm at B.
- Join BC to get the required triangle.

By measuring, we get ∠*B *= ∠*C *= 30°.

**Question: 5**

Draw △*ABC* in which ∠*C *= 90° and AC = BC = 4 cm.

**Solution:**

**Steps of construction:**

- Draw a line segment BC of length 4 cm.
- At C, draw ∠
*BCY*=90°. - Cut an arc on CY at a distance of 4 cm at A.
- Join AB. ABC is the required triangle.

**Question: 6**

Draw a triangle ABC in which BC = 4 cm, AB = 3 cm and ∠*B *= 45°. Also, draw a perpendicular from A on BC.

**Solution:**

**Steps of construction:**

- Draw a line segment AB of length 3 cm.
- Draw an angle of 45° and cut an arc at this angle at a radius of 4 cm at C.
- Join AC to get the required triangle.
- With A as centre, draw intersecting arcs at M and N.
- With centre M and radius more than half of MN, cut an arc on the opposite side of A.
- With N as centre and radius the same as in the previous step, cut an arc intersecting the previous arc at E.
- Join AE, it meets BC at D, then AE is the required perpendicular.

**Question: 7**

Draw a triangle ABC with AB = 3 cm, BC = 4 cm and ∠*B *= 60°. Also, draw the bisector of angles C and A of the triangle, meeting in a point O. Measure ∠*COA*.

**Solution:**

**Steps of construction:**

Draw a line segment BC = 4 cm.

Draw ∠*CBX *= 60°.

Draw an arc on BX at a radius of 3 cm cutting BX at A.

Join AC to get the required triangle.

**Angle bisector for angle A:**

- With A as centre, cut arcs of the same radius cutting AB and AC at P and Q, respectively.
- From P and Q cut arcs of same radius intersecting at R.
- Join AR to get the angle bisector of angle A.

**Angle bisector for angle C:**

- With A as centre, cut arcs of the same radius cutting CB and CA at M and N, respectively.
- From M and N, cut arcs of the same radius intersecting at T
- Join CT to get the angle bisector of angle C.

Mark the point of intersection of CT and AR as 0.

Angle ∠*COA *= 120°.

**All Chapter RD Sharma Solutions For Class 7 Maths**

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