RD Sharma Class 7 ex 7.3 Solutions Chapter 7 Algebraic Expressions

In this chapter, we provide RD Sharma Class 7 ex 7.3 Solutions Chapter 7 Algebraic Expressions for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 7 ex 7.3 Solutions Chapter 7 Algebraic Expressions Maths pdf, Now you will get step by step solution to each question.

Maths pdf, Now you will get step by step solution to each question.

TextbookNCERT
ClassClass 7
SubjectMaths
ChapterChapter 7
Chapter NameAlgebraic Expressions
ExerciseEx 7.3

RD Sharma Solutions for Class 7 Chapter 7 Decimals Ex 7.3 Download PDF

Chapter 7: Algebraic Expressions Exercise – 7.3

Question: 1

Place the last two terms of the following expressions in parentheses preceded by a minus sign:

(i) x + y – 3z + y    

(ii) 3x – 2y – 5z – 4

(iii) 3a – 2b + 4c – 5

(iv) 7a + 3b + 2c + 4

(v) 2a– b2 – 3ab + 6

(vi) a2 + b2 – c2 + ab – 3ac

Solution:

We have

(i) x + y – 3z + y = x + y – (3z – y)

(ii) 3x – 2y – 5z – 4 = 3x – 2y – (5z + 4)

(iii) 3a – 2b + 4c – 5 = 3a – 2b – (–4c + 5)

(iv) 7a + 3b + 2c + 4 = 7a + 3b – (–2c – 4)

(v) 2a– b2 – 3ab + 6 = 2a2 – b2 – (3ab – 6)

(vi) a2 + b2 – c+ ab – 3ac = a2 + b2 – c2 – (- ab + 3ac)

Question: 2

Write each of the following statements by using appropriate grouping symbols:

(i) The sum of a – b and 3a – 2b + 5 is subtracted from 4a + 2b – 7.

(ii) Three times the sum of 2x + y – [5 – (x – 3y)] and 7x – 4y + 3 is subtracted from 3x – 4y + 7

(iii) The subtraction of x– y2 + 4xy from 2x2 + y2 – 3xy is added to 9x2 – 3y2– xy.

Solution:

(i) The sum of a – b and 3a – 2b + 5 = [(a – b) + (3a – 2b + 5)].

This is subtracted from 4a + 2b – 7.

Thus, the required expression is (4a + 2b – 7) – [(a – b) + (3a – 2b + 5)]

(ii) Three times the sum of 2x + y – {5 – (x – 3y)} and 7x – 4y + 3 = 3[(2x + y – {5 – (x – 3y)}) + (7x – 4y + 3)]

This is subtracted from 3x – 4y + 7.

Thus, the required expression is (3x – 4y + 7) – 3[(2x + y – {5 – (x – 3y)}) + (7x – 4y + 3)]

(iii) The product of subtraction of x2– y2 + 4xy from 2x2 + y2 – 3xy is given by {(2x2 + y2 – 3xy) – (x2-y2 + 4xy)}

When the above equation is added to 9x2 – 3y– xy, we get

{(2x2 + y2 – 3xy) – (x– y+ 4xy)} + (9x– 3y2– xy))

All Chapter RD Sharma Solutions For Class 7 Maths

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