In this chapter, we provide RD Sharma Class 7 ex 6.3 Solutions Chapter 6 Exponents for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 7 ex 6.3 Solutions Chapter 6 Exponents Maths pdf, Now you will get step by step solution to each question.

Maths pdf, Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 7 |

Subject | Maths |

Chapter | Chapter 6 |

Chapter Name | Exponents |

Exercise | Ex 6.3 |

Table of Contents

**RD Sharma Solutions for Class 7 Chapter 6 Decimals** **Ex** **6.3 Download PDF**

**Chapter 6: Exponents Exercise – 6.3**

**Question: 1**

Express the following numbers in the standard form

(i) 3908.78

(ii) 5, 00, 00, 000

(iii) 3, 18, 65, 00, 000

(iv) 846 × 10^{7}

(v) 723 × 10^{9}

**Solution:**

(i) 3908.78 = 3.90878 × 10^{3}

Since, the decimal point is moved three places to the left

(ii) 5, 00, 00, 000 = 5, 00, 00, 000.00

= 5 × 10^{7}

Since, the decimal point is moved seven places to the left

(iii) 3, 18, 65, 00, 000 = 3, 18, 65, 00, 000.00

= 3.1865 × 10^{9}

Since, the decimal point is moved nine places to the left

(iv) 846 × 10^{7} = 8.46 × 10^{2} × 10^{7}

= 8.46 × 10^{9}

Since, the decimal point is moved two places to the left

(v) 723 × 10^{9} = 7.23 × 10^{2} × 10^{9}

= 7.23 × 10^{11}

Since, the decimal point is moved two places to the left

**Question: 2**

Write the following numbers in the usual form

(i) 4.83 × 10^{7}

(ii) 3.21 × 10^{5}

(iii) 3.5 × 10^{3}

**Solution:**

(i) 4.83 × 10^{7} = 483 × 10^{(}^{7}^{–}^{2}^{)}

= 483 × 10^{5}

= 4, 83, 00, 000

Since, the decimal point is moved two places to the right

(ii) 3.21 × 10^{5} = 321 × 10^{(}^{5}^{–}^{2}^{)}

= 321 × 103

= 3, 21, 000

Since, the decimal point is moved two places to the right

(ii) 3.5 × 10^{3} = 35 × 10^{(}^{3}^{–}^{1}^{)}

= 35 × 10^{2}

= 3,500

Since, the decimal point is moved one place to the right

**Question: 4**

Express the numbers appearing in the following statements in the standard form

(i) The distance between the earth and the moon is 384,000,000 metres.

(ii) Diameter of the earth is 1, 27, 56,000 metres.

(iii) Diameter of the sun is 1, 400, 000, 000 metres.

(iv) The universe is estimated to be about 12,000,000,000 years old.

**Solution:**

(i) The distance between the earth and the moon is 3.84 × 10^{8} metres.

Since, the decimal point is moved eight places to the left

(ii) Diameter of the earth is 1.2756 × 10^{7} metres.

Since, the decimal point is moved seven places to the left

(ii) Diameter of the sun is 1.4 × 10^{9} metres.

Since, the decimal point is moved nine places to the left

(iv) The universe is estimated to be about 1.2 × 10^{10} years old.

Since, the decimal point is moved ten places to the left

**All Chapter RD Sharma Solutions For Class 7 Maths**

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