In this chapter, we provide RD Sharma Class 7 ex 6.1 Solutions Chapter 6 Exponents for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 7 ex 6.1 Solutions Chapter 6 Exponents Maths pdf, Now you will get step by step solution to each question.
Maths pdf, Now you will get step by step solution to each question.
Textbook | NCERT |
Class | Class 7 |
Subject | Maths |
Chapter | Chapter 6 |
Chapter Name | Exponents |
Exercise | Ex 6.1 |
RD Sharma Solutions for Class 7 Chapter 6 Decimals Ex 6.1 Download PDF
Chapter 6: Exponents Exercise – 6.1
Question: 1
Find the values of each of the following:
(i) 132
(ii) 73
(iii) 34
Solution:
(i) 132 = 13 × 13
= 169
(ii) 73 = 7 × 7 × 7
= 343
(iii) 34 = 3 × 3 × 3 × 3
= 81
Question: 2
Find the value of each of the following:
(i) (-7)2
(ii) (-3)4
(iii) (-5)5
Solution:
We know that if ‘a’ is a natural number, then

We have,
(i) (-7)2 = (-7) × (-7)
= 49
(ii) (-3)4 = (-3) × (-3) × (-3) × (-3)
= 81
(iii) (-5)5 = (-5) × (-5) × (-5) × (-5) × (-5)
= -3125
Question: 3
Simply:
(i) 3 × 102
(ii) 22 × 53
(iii) 33 × 52
Solution:
(i) 3 × 102 = 3 × 10 × 10
= 3 × 100
= 300
(ii) 22 × 53 = 2 × 2 × 5 × 5 × 5
= 4 × 125
= 500
(iii) 33 × 52 = 3 × 3 × 3 × 5 × 5
= 27 × 25
= 675
Question: 4
Simply:
(i) 32 × 104
(ii) 24 × 32
(iii) 52 × 34
Solution:
(i) 32 × 104 = 3 × 3 × 10 × 10 × 10 × 10
= 9 × 10000
= 90000
(ii) 24 × 32 = 2 × 2 × 2 × 2 × 3 × 3
= 16 × 9
= 144
(iii) 52 × 34 = 5 × 5 × 3 × 3 × 3 × 3
= 25 × 81
= 2025
Question: 5
Simply:
(i) (-2) × (-3)3
(ii) (-3)2 × (-5)3
(iii) (-2)5 × (-10)2
Solution:
(i) (-2) × (-3)3 = (-2) × (-3) × (-3) × (-3)
= (-2) × (-27)
= 54
(ii) (-3)2 × (-5)3 = (-3) × (-3) × (-5) × (-5) × (-5)
= 9 × (-125)
= -1125
(iii) (-2)5 × (-10)2 = (-2) × (-2) × (-2) × (-2) × (-2) × (-10) × (-10)
= (-32) × 100
= -3200
Question: 6
Simply:
(i) (3/4)2
(ii) (-2/3)4
(iii) (- 4/5)5
Solution:

Question: 7
Identify the greater number in each of the following
(i) 25 or 52
(ii) 34 or 43
(iii) 35 or 53
Solution:
(i) 25 or 52
25 = 2 × 2 × 2 × 2 × 2
= 32
52 = 5 × 5
= 25
Therefore, 25 52
(ii) 34 or 43
= 34 = 3 × 3 × 3 × 3
= 81
= 43 = 4 × 4 × 4
= 64
Therefore, 34 43
(iii) 35 or 53
= 35 = 3 × 3 × 3 × 3 × 3
= 243
= 53 = 5 × 5 × 5
= 125
Therefore, 35 53
Question: 8
Express each of the following in exponential form
(i) (-5) × (-5) × (-5)

Solution:
(i) (-5) × (-5) × (-5) = (-5)3

Question: 9
Express each of the following in exponential form
(i) x × x × x × x × a × a × b × b × b
(ii) (-2) × (-2) × (-2) × (-2) × a × a × a
(iii) (-2/3) × (-2/3) × x × x × x
Solution:
(i) x × x × x × x × a × a × b × b × b = x4a2b3
(ii) (-2) × (-2) × (-2) × (-2) × a × a × a = (-2)4a3
(iii) (-2/3) × (-2/3) × x × x × x = (-2/3)2 x3
Question: 10
Express each of the following numbers in exponential form
(i) 512
(ii) 625
(iii) 729
Solution:
(i) 512 = 29
(iii) 625 = 54
(iii) 729 = 36
Question: 11
Express each of the following numbers as a product of powers of their prime factors
(i) 36
(ii) 675
(iii) 392
Solution:
(i) 36 = 2 × 2 × 3 × 3
= 22 × 32
(ii) 675 = 3 × 3 × 3 × 5 × 5
= 33 × 52
(iii) 392 = 2 × 2 × 2 × 7 × 7
= 23 × 72
Question: 12
Express each of the following numbers as a product of powers of their prime factors
(i) 450
(ii) 2800
(iii) 24000
Solution:
(i) 450 = 2 × 3 × 3 × 5 × 5
= 2 × 32 × 52
(ii) 2800 = 2 × 2 × 2 × 2 × 5 × 5 ×7
= 24 × 52 × 7
(iii) 24000 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5 × 5 × 5
= 25 × 3 × 53
Question: 13
Express each of the following as a rational number of the form p/q
(i) (3/7)2
(ii) (7/9)3
(iii) (-2/3)4
Solution:

Question: 14
Express each of the following rational numbers in power notation
(i) 49/64
(ii) – 64/125
(iii) -12/16
Solution:
(i) 49/64 = (7/8)2
Because 72 = 49 and 82 = 64
(ii) – 64/125 = (- 4/5)3
Because 43 = 64 and 53 = 125
(iii) – (1/216) = – (1/6)3
Because 13 = 1 and 63 = 216
Question: 15
Find the value of the following
(i) (-1/2)2 × 23 × (3/4)2
(ii) (-3/5)4 × (4/9)4 × (-15/18)2
Solution:
(i) (-1/2)2 × 23 × (3/4)2 = 1/4 × 8 × 9/16
= 9/8
(ii) (-3/5)4 × (4/9)4 × (-15/18)2 = 81/625 × 256/6561 × 225/324 = 64/18225
Question: 16
If a = 2 and b= 3, the find the values of each of the followimg
(i) (a + b)a
(ii) (ab)b
(iii) (b/a)b
(iv) (a/b + b/a)a
Solution:
(i) (a + b)a = (2 + 3)2
= (5)2
= 25
(ii) (ab)b = (2 × 3)3
= (6)3
= 216
(iii) (b/a)b = (3/2)3
= 27/8
(iv) (a/b + b/a)a = (2/3 + 3/2)2
= 169/36
All Chapter RD Sharma Solutions For Class 7 Maths
I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good marks in your exam.