RD Sharma Class 7 ex 3.3 Solutions Chapter 3 Decimals

In this chapter, we provide RD Sharma Class 7 ex 3.3 Solutions Chapter 3 Decimals for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 7 ex 3.3 Solutions Chapter 3 Decimals Maths pdf, Now you will get step by step solution to each question.

TextbookNCERT
ClassClass 7
SubjectMaths
ChapterChapter 3
Chapter NameDecimals
ExerciseEx 3.3

RD Sharma Solutions for Class 7 Chapter 3 Decimals Ex 3.3 Download PDF

Chapter 3: Decimals Exercise – 3.3

Question: 1

Divide:

(i) 142.45 by 10

(ii) 54.25 by 10

(iii) 3.45 by 10

(iv) 0.57 by 10

(v) 0.043 by 10

(vi) 0.004 by 10

Solution:

(i) 142.45 by 10

Shifting the decimal point by one place to the left

142.45/10

= 14.245

 (ii) 54.25 by 10

Shifting the decimal point by one place to the left

54.25/10

= 5.425

(iii) 3.45 by 10

Shifting the decimal point by one place to the left

3.45/10

0.345

(iv) 0.57 by 10

Shifting the decimal point by one place to the left

0.57/10

= 0.057

 (v) 0.043 by 10

Shifting the decimal point by one place to the left

0.043/10

= 0.0043

(vi) 0.004 by 10

Shifting the decimal point by one place to the left

0.004/10

= 0.0004

Question: 2

Divide:

(i) 459.5 by 100

(ii) 74.3 by 100

(iii) 5.8 by 100

(iv) 0.7 by 100

(v) 0.48 by 100

(vi) 0.03 by 100

Solution:

(i) 459.5 by 100

Shifting the decimal point by two places to the left

459.5/100

= 4.595

(ii) 74.3 by 100

Shifting the decimal point by two places to the left

74.3/100

= 0.743

(iii) 5.8 by 100

Shifting the decimal point by two places to the left

5.8/100

= 0.058

(iv) 0.7 by 100

Shifting the decimal point by two places to the left

0.7/100

= 0.007

 (v) 0.48 by 100

Shifting the decimal point by two places to the left

0.48/100

= 0.0048

(vi) 0.03 by 100

Shifting the decimal point by two places to the left

0.03/100

= 0.0003

Question: 3

Divide:

(i) 235.41 by 1000

(ii) 29.5 by 1000

(iii) 3.8 by 1000

(iv) 0.7 by 1000

Solution:

(i) 235.41 by 1000

Shifting the decimal point by three places to the left

235.41/1000

= 0.23541

(ii) 29.5 by 1000

Shifting the decimal point by three places to the left

29.51/000

= 0.0295

(iii) 3.8 by 1000

Shifting the decimal point by three places to the left

3.8/1000

= 0.0038

(iv) 0.7 by 1000

Shifting the decimal point by three places to the left

0.7/1000

= 0.007

Question: 4

Divide:

(i) 0.45 by 9

(ii) 217.44 by 18

(iii) 319.2 by 2.28

(iv) 40.32 by 9.6

(v) 0.765 by 0.9

(vi) 0.768 by 1.6

Solution:

(i) 0.45 by 9

= 0.45/9

= 0.05

(ii) 217.44 by 18

= 217.44/18

= 12.08

(iii) 319.2 by 2.28

= 319.2/2.28

(iv) 40.32 by 9.6

= 40.32/9.6

= 403.2/96

= 4.2

= 403.2/96 = 4.2

(v) 0.765 by 0.9

= 0.765/0.9

= 7.65/9

= 0.85

= 7.65/0.9 = 0.85

(vi) 0.768 by 1.6

= 0.768/1.6

= 7.68/16

= 0.48

Question: 5

Divide: 
(i) 16.64 by 20
(ii) 0.192 by 12
(iii) 163.44 by 24
(iv) 403.2 by 96
(v) 16.344 by 12
(vi) 31.92 by 228

Solution:

(i) 16.64 by 20

= 16.64/20

= 1.664/2

= 0.832

(ii) 0.192 by 12

= 0.192/12

= 0.016

(iii) 163.44 by 24

= 163.44/24

= 6.81

 (iv) 403.2 by 96

= 403.2/96

= 4.2

 (v) 16.344 by 12

= 16.344/12

= 1.362

(vi) 31.92 by 228

= 31.92/228

= 0.14

Question: 6

Divide:

(i) 15.68 by 20
(ii) 164.6 by 200
(iii) 403.80 by 30

Solution:

(i) 15.68 by 20 

=15.68/20

=1.568/2

= 0.784

(ii) 164.6 by 200

Question: 7

(i) 76 by 0.019

(ii) 88 by 0.08

(iii) 148 by 0.074

(iv) 7 by 0.014

(iii) 403.80 by 30

Solution:

(i) 76 by 0.019

= 76/0.019

= 76000/19

= 4000

(ii) 88 by 0.08

= 88/0.08

= 8800/8

=1100

(iii) 148 by 0.074

= 148/0.074

= 148000/74

= 2000

(iv) 7 by 0.014

= 70.014

= 7000/14

= 0.823

(iii) 403.80 by 30

= 403.80/30

Question: 8

Divide:

(i) 20 by 50

(ii) 8 by 100

(iii) 72 by 576

(iv) 144 by 15

Solution:

(i) 20 by 50 
= 20/50
 = 0.4
 (ii) 8 by 100 
= 8/100
By shifting the decimal point to the left
= 8/100
= 0.08
(iii) 72 by 576 
= 72/576
= 0.125

(iv)144 by 15 
= 144/15

= 9.6

Question: 9

A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it travel in 1 litre of petrol?

Solution:

Distance covered in 2.4 litres of petrol = 43.2 km

Distance covered in 1 litre of petrol = 43.2/2.4

= 18km

The distance travelled in 1 litre of petrol is 18 km

Question: 10

The total weight of some bags of wheat is 1743 kg. If each bag weights 49.8 kg, how many bags are there?

Solution:

Total weight of bags of wheat = 1743 kg

Each bag weight = 49.8 kg

No of bags = 1743/49.8

= 35

Therefore the total numbers of bags are 35

Question: 11

Shikha cuts 50 m of cloth into pieces of 1.25 m each. How many pieces does she get?

Solution:

Total length of cloth = 50 m

Length of each piece of cloth = 1.25 m

Number of pieces = 50/1.25

= 5000/125

= 40 pieces

Therefore Shikha got 40 pieces

Question: 12

Each side of a rectangular polygon is 2.5 cm in length. The perimeter of the polygon is 12.5 cm. How many sides does the polygon have?

Solution:

Length of each side of rectangular polygon = 5.2 cm
Perimeter of polygon = 12.5 cm
No of sides polygon has = 12.5 cm
No of sides polygon have = 12.5/2.5

= 5

Therefore the sides of the polygon is 5

Question: 13

The product of two decimals is 42.987. If one of them is 12.46, find the other.

Solution:

We have,

The product of the given decimals = 42.987

 one decimal = 12.46

The other decimal = 42.987/12.46

= 3.45

The number is 3.45

Question: 14

The weight of 34 bags of sugar is 3483.3 kg. If all bags weigh equally, find the weight of each bag.

Solution:

Total weight of sugar = 3483.3kg

No of bags = 34

Weight of each bag = 3483.3/34

= 102.45 kg

Therefore weight of each bag is 102.45 kg

Question: 15

How many buckets of equal capacity can be filled from 586.5 litres of water, if each bucket has capacity of 8.5 litres?

Solution:

Capacity of each bucket = 805 litres

Total water available = 586.5 litres

Number of buckets = 805/586.5

= 69

Total number of buckets is 69

All Chapter RD Sharma Solutions For Class 7 Maths

I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good marks in your exam.

Leave a Comment

Your email address will not be published. Required fields are marked *