In this chapter, we provide RD Sharma Class 7 ex 3.2 Solutions Chapter 3 Decimals for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 7 ex 3.2 Solutions Chapter 3 Decimals Maths pdf, Now you will get step by step solution to each question.

RD Sharma Solutions for Class 7 Chapter 3 Decimals Ex 3.2 Download PDF

Chapter 3: Decimals Exercise – 3.2

Question: 1

Find the product:

(i) 4.74 x 10

(ii) 0.45 x 10

(iii) 0.0215 x 10

(iv) 0.0054 x 100

Solution:

(i) 4.74 x 10

Shifting the decimal point by one place to the right

4.74 x 10 = 47.4

(ii) 0.45 x 10

Shifting the decimal point by one place to the right

0.45 × 10 = 4.5

(iii) 0.0215 x 10

Shifting the decimal point by one place to the right

0.0215 × 10 = 0.215

(iv) 0.0054 x 100

Shifting the decimal point by two places to the right

0.0054 × 100 = 0.054

Question: 2

Find the product:

(i) 35.853 x 100

(ii) 42.5 x 100

(iii) 12.075 x 100

(iv) 100 x 0.005

Solution:

(i) 35.853 x 100

Shifting the decimal point by two places to the right

35.853 = 3585.3

(ii) 42.5 x 100

Shifting the decimal point by two places to the right

42.5 × 100 = 4250

(iii) 12.075 x 100

Shifting the decimal point by two places to the right

12.075 × 100 = 1207.5

(iv) 100 x 0.005

Shifting the decimal point by two places to the right

0.005 × 100 = 0.5

Question: 3

Find the product:

(i) 2.506 x 1000

(ii) 20.708 x 1000

(iii) 0.0529 x 1000

(iv) 1000 x 0.1

Solution:

(i) 2.506 x 1000

Shifting the decimal point by three places to the right

2.506 × 1000 = 2506

(ii) 20.708 x 1000

Shifting the decimal point by three places to the right

20.708 × 1000 = 20708

(iii) 0.0529 x 1000

Shifting the decimal point by three places to the right

0.0529 × 1000 = 52.9

(iv) 1000 x 0.1

Shifting the decimal point by three places to the right

0.1 × 1000 = 100

Question: 4

Find the product:

(i) 3.4 x 17

(ii) 0.745 x 12

(iii) 28.73 x 47

(iv) 0.0415 x 59

Solution:

(i) 3.4 x 17

Multiply the number without looking into the decimal points

3.4 × 17 = 578

Mark the decimal point in the product to have one place of decimal as there in the given decimal

= 57.8

(ii) 0.745 x 12

Multiply the number without looking into the decimal points

745×12 = 8940

Mark the decimal point in the product to have three places of decimal as there in the given decimal

0.745 x 12= 8.940

(iii) 28.73 x 47

Multiply the number without looking into the decimal points

2873 × 47 = 135031

Mark the decimal point in the product to have two places of decimal as there in the given decimal

28.73 × 47 = 1350.31

(iv) 0.0415 x 59

Multiply the number without looking into the decimal points

415 × 59 = 24485

Mark the decimal point in the product to have two places of decimal as there in the given decimal

0.0415 × 59 = 2.4485

Question: 5

Find:

(i) 1.07 x 0.02

(ii) 211.9 x 1.13

(iii) 10.05 x 1.05

(iv) 13.01 x 5.01

Solution:

(i) 1.07 x 0.02

Multiply the number without looking into the decimal points

107× 2 = 214

Sum of the decimal places in the given decimals is 2 + 2 = 4

Mark the decimal point in the product to have four places of decimals

1.07 × 0.02 = 0.0214

(ii) 211.9 x 1.13

Multiply the number without looking into the decimal points

2119 × 113 = 239447

Sum of the decimal places in the given decimals is 1+ 2 = 3

Mark the decimal point in the product to have three places of decimals

211.9 × 1.13 = 239.447

(iii) 10.05 x 1.05

Multiply the number without looking into the decimal points

1005 × 105 = 105525

Sum of the decimal places in the given decimals is 2 + 2 = 4

Mark the decimal point in the product to have four places of decimals

10.05 × 1.05 = 10.5525

(iv) 13.01 x 5.01

Multiply the number without looking into the decimal points

1301 × 501 = 651801

Sum of the decimal places in the given decimals is 2+ 2 = 4

Mark the decimal point in the product to have four places of decimals

13.01 × 5.01 = 65.1801

Question: 6

Find the area of a rectangle whose length is 5.5 m and breadth is 3.4 m.

Solution:

We have

Length of rectangle = 5.5 m

Breadth of rectangle = 3.4 m

Area of rectangle = Length × Breadth

= 5.5 x 3.4

=18.7 m²

Question: 7

If the cost of a book is Rs 25.75, find the cost of 24 such books.

Solution:

Cost of one book = Rs.25.75

Therefore cost of 24 books = 25.75 x 24

= Rs.618.00

Question: 8

A car covers a distance of 14.75 km in one litre of petrol. How much distance will it cover in 15.5 litres of petrol?

Solution:

We have,

Distance covered in one litre of petrol = 14.75 km

Distance covered in 15.5 litres of petrol = 14.75 x 15.5

= 228.625 km

Question: 9

One kg of rice costs Rs 42.65. What will be the cost of 18.25 kg of rice?

Solution:

Cost of one kg rice = 42.65

Cost of 18.25kg = 42.65 x 18.25

= Rs.778.3625

Question: 10

One metre of cloth costs Rs 152.50. What is the cost of 10.75 metres of cloth?

Solution:

We have,

One metre of cloth cost = Rs.152.50

Cost of 10.75 metres =10.75 x 152.50

= Rs.1639.375

All Chapter RD Sharma Solutions For Class 7 Maths

I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good marks in your exam.