In this chapter, we provide RD Sharma Class 6 ex 5.3 Solutions Chapter 5 Negative Numbers and Integers for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 6 ex 5.3 Solutions Chapter 5 Negative Numbers and Integers Maths pdf, Now you will get step by step solution to each question.
Textbook | NCERT |
Class | Class 6 |
Subject | Maths |
Chapter | Chapter 5 |
Chapter Name | Negative Numbers and Integers |
Exercise | Ex 5.3 |
RD Sharma Solutions for Class 6 Chapter 5 Negative Numbers and Integers Ex 5.3 Download PDF
Chapter 5: Negative Numbers and Integers – Exercise 5.3
Negative Numbers and Integers – Exercise – 5.3 – Q.1
Ans.
(i) Additive inverse of 52 is -52.
(ii) 176
(iii) 0
(iv) -1
Negative Numbers and Integers – Exercise – 5.3 – Q.2
Ans.
(i) Success – or – 42 is = – 42 + (-1)
= 1- 42
= – 41
(ii) -1 + 1 = 0
(iii) 0 + 1 =1
(iv) – 200 + 1 = –199
(v) – 99 + 1 = –98.
Negative Numbers and Integers – Exercise – 5.3 – Q.3
Ans.
(i) predecessor of 0 is ⟹ 0 -1 = -1
(ii) 1 – 1 = 0
(iii) -1 -1 = -2
(iv) -125 -1 = -126
(v) 1000 -1 = 999
Negative Numbers and Integers – Exercise – 5.3 – Q.4
Ans.
(i) True
(ii) False
(iii) False
(iv) False
(v) False
Negative Numbers and Integers – Exercise – 5.3 – Q.5
Ans.
Integers whose absolute values less than 5 are
– 4, – 3, – 2, – 1, 0, 1, 2, 3, 4.
Negative Numbers and Integers – Exercise – 5.3 – Q.6
Ans.
(i) True
(ii) False
(iii) True
(iv) True
Negative Numbers and Integers – Exercise – 5.3 – Q.7
Ans.
+ | – 6 | – 4 | – 2 | 0 | 2 | 4 | 6 |
6 | 0 | 2 | 4 | 6 | 8 | 10 | 12 |
4 | – 2 | 0 | 2 | 4 | 6 | 8 | 10 |
2 | – 4 | – 2 | 0 | 2 | 4 | 6 | 8 |
0 | – 6 | -4 | – 2 | 4 | 2 | 4 | 6 |
– 2 | – 8 | -6 | – 4 | – 2 | 0 | 2 | 4 |
– 4 | – 10 | -8 | – 6 | – 4 | – 2 | 0 | 2 |
– 6 | – 12 | -10 | – 8 | – 6 | – 4 | – 2 | 0 |
(i) (+6, -6), (4, -4), (3, -3), (2, -2), (1, -1), (0, 0)
(ii) yes by commutativity of Addition
(-4) + (-2) = (-2) + (-4)
(iii) By existence of additive identity
0 + (-6) = -6 [∵ 0 + a = a]
Negative Numbers and Integers – Exercise – 5.3 – Q.8
Ans.
(i) x +1 = 0
⟹ x + 1 – 1 = 0 – 1 [subtract ∵ on both sides]
⟹ x = -1
(ii) x + 5 = 0
x + 5 – 5 = 0 – 5
x + 0 = -5
⟹ x = -5
(iii) -3 + x = 0
3 – 3 + x = 0 + 3
x = 3
(iv) x + (-8) = 0
x – 8 = 0
x – 8 + 8 = 0 + 8
x = 8
(v) 7 + x = 0
⟹ 7 + x – 7 = 0 – 7
⟹ x = – 7
(vi) x + 0 = 0
x = 0.
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