# RD Sharma Class 6 ex 19.4 Solutions Chapter 19 Geometrical Constructions

In this chapter, we provide RD Sharma Class 6 ex 19.4 Solutions Chapter 19 Geometrical Constructions for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 6 ex 19.4 Solutions Chapter 19 Geometrical Constructions Maths pdf, Now you will get step by step solution to each question.

# Chapter 19: Geometrical Constructionss Exercise 19.4

### Question: 1

Construct the following angles with the help of protractor:

45°, 67°, 38°, 110°, 179°, 98°, 84°.

### Solution:

We draw a ray OA.

We place the protractor on OA such that its center coincides with the point 0 and the diameter of the protractor coincides with OA.

We mark a point B against the mark of 45° on the protractor.

We remove the protractor and draw OB. ∠AOB is the required angle of 45°.

Similarly, we draw the angles 67°, 38°, 110°, 179°, 98° and 84°.

### Question: 2

Draw two rays PQ and RS as shown in figure. Using the protractor, construct angles of 15° and 138° with one arm PQ and RS respectively.

### Solution:

(i) Draw a ray PQ as given in the question.

Place the protractor on the ray PQ such that its center coincides with the point P and the diameter of the protractor coincides with PQ.

Mark a point B against the mark of 15° on the protractor.

Remove the protractor and draw PB. ∠QPB is the required angle of 15°.

(ii) Draw a ray RS as given in the question.

Place the protractor on ray RS such that its centre coincides with the point R and diameter of the protractor coincides with RS.

Mark a point T against the mark of 138° on the protractor.

Remove the protractor and draw RJ.

∠SRTIIs the required angle of 138°.

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