Here we provide RD Sharma Class 12 Ex 22.6 Solutions Chapter 22 Differential Equations for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 12 Ex 22.6 Solutions Chapter 22 Differential Equations book pdf download. Now you will get step-by-step solutions to each question.

Textbook | NCERT |

Class | Class 12th |

Subject | Maths |

Chapter | 22 |

Exercise | 22.6 |

Category | RD Sharma Solutions |

**RD Sharma Class 12 Ex 22.6 Solutions Chapter 22 Differential Equations**

**Question 1. Solve the following differential equation**

**Solution:**

From the question it is given that,

Transposing we get,

By cross multiplication,

Integrating on both side, we will get,

log (1 + y^{2}) = – 2x + c_{1}

Therefore, log [1 + y^{2}] + x = c

**Question 2. Solve the following differential equation **

**Solution:**

From the question it is given that,

By cross multiplication,

Integrating on both side, we will get,

**Question 3. Solve the following differential equation:**

**Solution:**

From the question it is given that,

By cross multiplication,

As we know that, = cosec x

cosec^{2}y dy = dx

Integrating on both side, we will get,

∫cosec^{2} y dy = ∫dx + c

– cot y = x + c

**Question 4. Solve the following differential equation:**

**Solution:**

From the question it is given that,

We know that, 1 – cos 2y = 2sin^{2}y and 1 + cos 2y = 2 cos^{2}y

So,

Also we know that, = tan θ

By cross multiplication,

Integrating on both side, we get,

∫cot^{2}y dy = ∫dx

∫ (cosec^{2}y – 1) dy = ∫dx

– cot y- y + c = x

c = x + y + cot y

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