In this chapter, we provide RD Sharma Class 10 Ex 6.2 Solutions Chapter 6 Trigonometric Identities for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 10 Ex 6.2 Solutions Chapter 6 Trigonometric Identities pdf, Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 6 |

Chapter Name | Trigonometric Ratios |

Exercise | 6.2 |

Category | RD Sharma Solutions |

Table of Contents

**RD Sharma Solutions for Class 10 Chapter** **6 ****Trigonometric Ratios** Ex 6.2 Download PDF

**Trigonometric Ratios**Ex 6.2 Download PDF

**Chapter 6: Trigonometric Identities Exercise – 6.2**

**Question: 1**

If cos θ = 4/5, find all other trigonometric ratios of angle θ.

**Solution: **

We have: sin θ = 1 – cos^{2}θ

= 3/5

Therefore, sin θ = 3/5

**Question: 2**

If sin θ = 1/√2, find all other trigonometric ratios of angle θ.

**Solution: **

We have,

=1/1

=1

**Question: 3**

**Solution: **

We know that

Substituting it in equation (1) we get

**Question: 4**

**Solution: **

We know that

sec θ = 5/4

= 1/(5/4)

= 4/5

= cos θ

Therefore, We get

**Question: 5**

**Solution: **

= 12/13

i. e. We get

= 25/1

= 25.

**Question: 6**

**Solution: **

= cos θ = sin θ × cot θ

= 1/2

Therefore, on substituting we get

= 3/5.

**Question: 7**

**Solution: **

We know that

= 1.

= 1/1

= 1

On substituting we get:

= 4/2

= 2

**Question: 8**

**Solution: **

= 2

cos θ = cot θ. sin θ

On substituting we get:

= 21/8

**Question: 9**

**Solution:**

On substituting we get

= 40/4

= 10

**Question: 10**

If √3 tan θ = sin θ, find the value of sin^{2}θ – cos^{2}θ.

**Solution: **

= sin^{2}θ – cos^{2}θ

= 1/3

**Question: 11**

**Solution: **

= 12/13

= 9/3

= 3

**Question: 12**

If sin θ + cos θ =√2 cos(90°- θ), find cot θ.

**Solution: **

= sin θ + cos θ = √2 sin θ [cos (90 – θ) = sin θ]

⇒ cos θ = √2 sin θ – sin θ

⇒ cos θ = sin θ (√2 – 1)

Divide both sides with sin θ we get

= √2 – 1.

**Question: 13**

If 2 sin^{2 }θ − cos^{2}θ = 2, then find the value of θ.

**Solution: **

2 sin^{2 }θ − cos^{2} θ = 2

⇒ 2 sin^{2} θ − (1 − sin^{2} θ) = 2

⇒ 2 sin^{2} θ − 1 + sin^{2} θ = 2

⇒ 3 sin^{2} θ = 3

⇒ sin^{2} θ = 1

⇒ sin θ = 1

⇒ sin θ = sin 90°

⇒ θ = 90°

**Question: 14**

If √3 tan θ – 1 = 0, find the value of sin^{2} θ – cos^{2} θ.

**Solution: **

√3 tan θ = tan 30° θ = 30°

Now, sin^{2}θ – cos^{2} θ = sin^{2} (30°) – cos^{2} (30°)

**All Chapter RD Sharma Solutions For Class10 Maths**

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