In this chapter, we provide RD Sharma Class 10 Ex 14.1 Solutions Chapter 14 Coordinate Geometry for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 10 Ex 14.1 Solutions Chapter 14 Coordinate Geometry pdf, Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 14 |

Chapter Name | Coordinate Geometry |

Exercise | 14.1 |

Category | RD Sharma Solutions |

Table of Contents

**RD Sharma Solutions for Class 10 Chapter** **14**** Coordinate Geometry** Ex 14.1 Download PDF

**Coordinate Geometry**Ex 14.1 Download PDF

**Chapter 14: Coordinate Geometry Exercise – 14.1**

**Question: 1**

On which axis do the following points lie?

(i) P (5,0)

(ii) Q (0 — 2)

(iii) R (-4, 0)

(iv) S (0, 5)

**Solution:**

(i) P (5, 0) lies on x – axis

(ii) Q (0, -2) lies on y – axis

(iii) R (-4, 0) lies on x – axis

(iv) S (0, 5) lies on y – axis

**Question: 2**

Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when

(i) A coincides with the origin and AB and AB and coordinate axes are parallel to the sides AB and AD respectively.

(ii) The center of the square is at the origin and coordinate axes are parallel to the sides AB and AD respectively.

**Solution:**

(i) Coordinate of the vertices of the square of side 2a are:

A (0, 0), B (2a, 0), C (2a, 2a) and D (0, 2a)

(ii) Coordinate of the vertices of the square of side 2a are:

A (a, a), B (- a, a), C (- a, a) and (a, – a)

**Question: 3**

The base PQ of two equilateral triangles PQR and PQR’ with side 2a lies along y-axis such that the mid-point of PQ is at the origin. Find the coordinates of the vertices R and R’ of the triangles.

**Solution:**

We have two equilateral triangle PQR and PQR’ with side 2a.

O is the mid-point of PQ.

In ∆Q0R. ∠QOR = 90°

Hence, by Pythagoras theorem

OR^{2} + OQ^{2} = QR^{2}

OR^{2} = (2a)^{2} – (a)^{2}

OR^{2} = 3a^{2}

OR = √(3) a

Coordinates of vertex R is (√3a, 0) and coordinate of vertex R’ is (- √3a,

**All Chapter RD Sharma Solutions For Class10 Maths**

I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good