In this chapter, we provide RD Sharma Class 10 Ex 1.3 Solutions Chapter 1 Real Numbers for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 10 Ex 1.3 Solutions Chapter 1 Real Numbers pdf, Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 1 |

Chapter Name | Real Numbers |

Exercise | 1.3 |

Category | RD Sharma Solutions |

**RD Sharma Solutions for Class 10 Chapter** **1 Real Numbers Ex 1.3 Download PDF**

**Chapter 1: Real Numbers Exercise – 1.3**

**Question: 1**

Express each of the following integers as a product of its prime.

1. 420

2. 468

3. 945

4. 7325

**Solution:**

To express: each of the following numbers as a product of their prime factors

1. 420

420 = 2 × 2 × 3 × 5 × 7

2. 468

468 = 2 × 2 × 3 × 3 × 13

3. 945

945 = 3 × 3 × 3 × 5 × 7

4. 7325

7325 = 5 × 5 × 293

**Question: 2**

Determine the prime factorization of each of the following positive integer:

1. 20570

2. 58500

3. 45470971

**Solution:**

To Express: Each of the following numbers as a product of their prime factors.

1. 20570

20570 = 2 × 5 × 11 × 11 × 17

2. 58500

58500 = 2 × 2 × 3 × 3 × 5 × 5 × 5 × 13

3. 45470971

45470971 = 7 × 7 × 13 × 13 × 17 × 17 × 19

**Question: 3**

Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.

**Solution:**

Why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.

We can see that both the numbers have common factor 7 and 1.

7 × 11 × 13 + 13 = (77 + 1) × 13 = 78 × 13

7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 = (7 × 6 × 4 × 3 × 2 + 1) × 5 = 1008 × 5

And we know that composite numbers are those numbers which have at least one more factor other than 1.

Hence after simplification we see that both numbers are even and therefore the given two numbers are composite numbers

**Question: 4**

Check whether 6^{n} can end with the digit 0 for any natural number n.

**Solution:**

To Check: Whether 6^{n} can end with the digit 0 for any natural number n.

We know that 6^{n} = (2 × 3)^{n}

6^{n} = 2^{n }× 3^{n}

Therefore, prime factorization of 6^{n} does not contain 5 and 2 as a factor together. Hence 6^{n} can never end with the digit 0 for any natural number n.

**All Chapter RD Sharma Solutions For Class10 Maths**

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