RD Sharma Class 9 Solutions Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS

In this chapter, we provide RD Sharma Solutions for Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Solutions for Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS Maths pdf, free RD Sharma Solutions for Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS Maths book pdf download. Now you will get step by step solution to each question.

RD Sharma Solutions for Class 9 Chapter 19 Surface Areas and Volume of a Circular Cylinder VSAQS Download PDF

Question 1.
Write the number of surface of a right circular cylinder.
Solution:
Three, two circular and one curved.

Question 2.
Write the ratio of total surface area to the curved surface area of a cylinder of radius r and height h.
Solution:
∵ Radius = r
and height = h
∴ Curved surface area = 2πrh
and total surface area = 2πr(h + r)
∴ Ratio = 2πr(h + r) : 2πrh
= h + r : h

Question 3.
The ratio between the radius of the base and height of a cylinder is 2 : 3. If its volume is 1617 cm3, find the total surface area of the cylinder.
Solution:
Ratio in radius and height of the cylinder = 2 : 3
Let radius (r) = 2x
Then height (h) = 3x
∴ Volume = πr²h

Question 4.
If the radii of two cylinders are in the ratio 2 : 3 and their heights are in the ratio 5 : 3, then find the ratio of their volumes.
Solution:
Ratio of radii of two cylinder = 2:3
Let radius of first cylinder (r₁) = 2x
and second cylinder (r₂) = 3x
and ratio in their heights = 5:3
Let height of first cylinder (h₁) = 5y
and height of second (h₂) = 3y
∴ Volume of the first cylinder =πr²h
= π x (2x)² x 5y = 20πx²y
and volume of second cylinder = π(3x)2 x 3y = 27πx²y
Now ratio between then,
= 20πx²y: 21πx²y
= 20 : 27

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