In this chapter, we provide RD Sharma Class 8 Solutions Chapter 8 Division of Algebraic Expressions Ex 8.4 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 8 Solutions Chapter 8 Division of Algebraic Expressions Ex 8.4 Maths pdf, free RD Sharma Class 8 Solutions Chapter 8 Division of Algebraic Expressions Ex 8.4 book pdf download. Now you will get step by step solution to each question.
Textbook | NCERT |
Class | Class 8 |
Subject | Maths |
Chapter | Chapter 8 |
Chapter Name | Division of Algebraic Expressions |
Exercise | Ex 8.4 |
RD Sharma Solutions for Class 8 Chapter 8 Division of Algebraic Expressions Ex 8.4 Download PDF
Question 1.
5x3 – 15x2 + 25x by 5x
Solution:
Question 2.
4z3 + 6z2-zby −12 z
Solution:
Question 3.
9x2y – 6xy + 12xy2 by −32 xy
Solution:
Question 4.
3x2y2 + 2x2y + 15xy by 3xy
Solution:
Question 5.
x2 + 7x + 12 by x + 4
Solution:
Question 6.
4y2 4 + 3y + −12 by 2y + 1
Solution:
Question 7.
3x3 + 4x2 + 5x + 18 by x + 2
Solution:
Question 8.
14x2 – 53x + 45 by 7a – 9
Solution:
Question 9.
-21 + 71x – 31x2 – 24ax3 by 3 – 8ax
Solution:
Question 10.
3y4 – 3y3 – 4y2 – 4y by y2 – 2y
Solution:
Question 11.
2y5 + 10y4 + 6y3 + y2 + 5y + 3 by 2y3 + 1
Solution:
Question 12.
x4 – 2x3 + 2x2 + x + 4 by x2 + x + 1
Solution:
Question 13.
m3 – 14m2 + 37m – 26 by m2 – 12m + 13
Solution:
Question 14.
x4 + x2 + 1 by x2 + x + 1
Solution:
Question 15.
x5 + x4 + x3+x2 + x+ 1 by x3 + 1
Solution:
Divide each of the following and find the quotient and remainder :
Question 16.
14x3 – 5x2 + 9x -1 by 2x – 1
Solution:
Question 17.
6x3 – x2 – 10x – 3 by 2x – 3
Solution:
Question 18.
6x3+ 11x2 – 39x – 65 by 3x2 + 13x + 13
Solution:
Question 19.
30a4 + 11a3-82a2– 12a + 48 by 3a2 + 2a- 4
Solution:
Question 20.
9x4 – 4x2 + 4 by 3x2 – 4x + 2
Solution:
Question 21.
Verify division algorithm i.e., Dividend = Divisor * Quotient + Remainder, in each of the following. Also, write the quotient and remainder :
Solution:
Question 22.
Divide 15y4 + 16y3 + 103 y – 9y2 – 6 by 3y – 2
Write down the co-efficients of the terms in the quotient.
Solution:
Question 23.
Using division of polynomials state whether.
(i) x + 6 is a factor of x2 – x – 42
(ii) 4x – 1 is a factor of 4x2 – 13x – 12
(iii) 2y – 5 is a factor of 4y4 – 10y3 – 10y2 + 30y -15
(iv) 3y + 5 is a factor of 6y5 + 15y + 16y + 4y+ 10y – 35
(v) z2 + 3 is a factor of z5– 9z
(vi) 2x2 – x + 3 is a factor of 60x5-x4 + 4x3 – 5x2 -x- 15
Solution:
Question 24.
Find the value of ‘a’, if x + 2 is a factor of 4x4 + 2x3 – 3x2 + 8x + 5a.
Solution:
Question 25.
What must be added to x4 + 2x3 — 2x2 + x – 1 so that the resulting polynomial is exactly divisible by x2 + 2x – 3.
Solution:
All Chapter RD Sharma Solutions For Class 8 Maths
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