In this chapter, we provide RD Sharma Class 8 Solutions Chapter 7 Factorization Ex 7.3 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 8 Solutions Chapter 7 Factorization Ex 7.3 Maths pdf, free RD Sharma Class 8 Solutions Chapter 7 Factorization Ex 7.3 Maths book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 8 |

Subject | Maths |

Chapter | Chapter 7 |

Chapter Name | Factorization |

Exercise | Ex 7.3 |

**RD Sharma Solutions for Class 8 Chapter 7 Factorization Ex 7.3** **Download PDF**

**Factorize each of the following algebraic expressions.**

**Question 1.6x (2x – y) + 7y (2x – y)Solution:**6x (2x – y) + 7y (2x – y)

= (2x – y) (6x + 7y)

[∵ (2x – y) is common]

**Question 2.**

**2r (y – x) + s (x – y)**

**Solution:**

2r (y – x) + s (x – y)

-2r (x – y) +s (x – y)

= (x – y) (-2r + s) [(x – y) is common]

= (x-y) (s-2r)

**Question 3.7a (2x – 3) + 2b (2x – 3)**

**Solution:**

7a (2x – 3) + 3b (2x – 3)

= (2x – 3) (7a + 3b) [(2x – 3) is common]

**Question 4.**

**9a (6a – 5b) – 12a**

^{2}(6a – 5b)**Solution:**

9a (6a – 5b) – 12a

^{2}(6a – 5b)

HCF of 9 and 12 = 3

∴ 3a (6a – 5b) (3 – 4a)

{(6a – 5b) is common}

**Question 5.5 (x – 2y) ^{2} + 3 (x – 2y)**

**Solution:**

5 (x – 2y)

^{2}+ 3 (x – 2y)

= 5 (x – 2y) (x – 2y) + 3 (x – 2y)

= (x – 2y) {5 (x – 2y) + 3}

{(x – 2y) is common}

= (x – 2y) (5x – 10y + 3)

**Question 6.**

**16 (2l – 3m)**

^{2}– 12 (3m – 2l)**Solution:**

16 (2l – 3m)

^{2}– 12 (3m-2l)

= 16 (2l – 3m) (2l – 3m) + 12 (2l – 3m)

HCF of 16, 12 = 4 4 (2l-3m) {4 (2l- 3m) + 3}

{(2l – 3m) is common}

= 4 (2l -3m) (8l- 12m+ 3)

**Question 7.**

**3a (x – 2y) – b (x – 2y)**

**Solution:**

3a (x – 2y) – b (x – 2y)

= (x – 2y) (3a – b)

{(x – 2y) is common}

**Question 8.**a

^{2}(x + y) + b

^{2}(x + y) + c

^{2}(x + y)

**Solution:**

a

^{2}(x + y) + b

^{2}(x + y) + c

^{2}(x + 3’)

= (x + y) (a

^{2}+ b

^{2}+ c

^{2})

{(x + y) is common}

**Question 9.(x-y) ^{2} + (x -y)**

**Solution:**

(x – y)

^{2}+ (x- y) = (x – y) (x – y) + (x – y)

= (x – y) (x – y + 1) {(a – y) is common}

**Question 10.**

**6 (a + 2b) – 4 (a + 2b)**

^{2}**Solution:**

6 (a + 2b) – 4 (a + 2b)

^{2}

= 6 (a + 2b) – 4 (a + 2b) (a + 2b)

HCF of 6, 4 = 2

= 2 {a + 2b) {3 – 2 {a + 2b)

{2 (a + b) is common}

= 2 (a + 2b) (3-2 a- 4b)

**Question 11.**

**a (x -y) + 2b (y – x) + c (x -y)**

^{2}**Solution:**

a (x -y) + 2b (y – x) + c (x -y)

^{2}

= a (x – y) – 2b (x – y) + c (x – y) {x – y)

= (x – y) {x – 2b + c (x – y)}

{(a – y) is common}

= (a – y) (a – 2b + cx – cy)

**Question 12.– 4 (a – 2y) ^{2} + 8 (a – 2y)**

**Solution:**

– 4 (x – 2y)

^{2}+ 8 (x – 2y)

= – 4 (x – 2y) (x – 2y) + 8 (x – 2y)

{- 4 (x – 2y) is common}

= – 4 (x – 2y) (x – 2y – 2)

= 4 (x – 2y) (2 – x + 2y)

**Question 13.**

**x**

^{3}(a – 2b) + a^{2}(a – 2b)**Solution:**

x

^{3}(a – 2b) + x

^{2}(a – 2b)

HCF of x

^{3}, x

^{2}= x

^{2∴ }x

^{2}(a – 2b) (x + 1)

{x

^{2}(x – 2b) is common}

= x

^{2}(x – 2b) (x + 1)

**Question 14.**

**(2x – 3y) (a + b) + (3x – 2y) (a + b)**

**Solution:**

(2x – 3y) (a + b) + (3x – 2y) (a + b)

= (a + b) {2x – 3y + 3x – 2y}

{(x + b) is common}

= (a + b) (5x – 5y)

= 5 (a + b) (x – y)

**Question 15.4 (x + y) (3a – b) + 6 (a + y) (2b – 3a)**

**Solution:**

4 (x + y) (3a – b) + 6 (a + y) (2b – 3a)

= 4 (x + y) (3a – b) – 6 (x + y) (3a – 2b)

HCF of 4, 6 = 2

= 2 (x + y) {2 (3a – b) – 3 (3a – 2b)}

= 2 (x + 3) {6a – 2b – 9a + 6b}

= 2 (x +y) {-3a + 4b}

= 2 (x + y) (4b – 3a)

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