In this chapter, we provide RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.3 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.3 Maths pdf, free RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.3 Maths book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 8 |

Subject | Maths |

Chapter | Chapter 6 |

Chapter Name | Algebraic Expressions and Identities |

Exercise | Ex 6.3 |

**RD Sharma Solutions for Class 8 Chapter 6 Algebraic Expressions and Identities Ex 6.3** **Download PDF**

**Find each of the following products (1-8)****Question 1.**

**5x**

^{2}x 4x^{3}**Solution:**

5x

^{2}x 4x

^{3}= 5 x 4 x x

^{2}x x

^{3}

= 20x

^{2 + 3}= 20x

^{s}

**Question 2.3a ^{2} x 4b^{4}Solution:**-3a

^{2}x 4b

^{4}= -3 x 4 x a

^{2}b

^{4}= -12a

^{2}b

^{4}

**Question 3.**

**(-5xy) x (-3x**

^{2}yz)**Solution:**

(-5xy) x (-3x

^{2}yz)

= (-5) x (-3)xy x x

^{2}yz

= 15x

^{1 + }

^{2}xy

^{1+ 1}z= 15x

^{3}y

^{2}z

**Question 4.****Solution:**

**Question 5.****Solution:**

**Question 6.****Solution:**

**Question 7.****Solution:**

**Question 8.****Solution:**

**Find each of the following products : (9-17)**

**Question 9.**

**(7ab) x (-5ab**

^{2}c) x (6abc^{2})**Solution:**

(7ab) x (-5ab

^{2}c) x (6abc

^{2})

= 7 x (-5) x 6 x a x a x a x b x b

^{2}x b x c x c

^{2}=-210 x a

^{1+1+1 }x b

^{1+2+1}x c

^{1+2}=-210 x a

^{3}b

^{4}c

^{3}

**Question 10.(-5a) x (-10a ^{2}) x (-2a^{3})**

**Solution:**

(-5a) x (-10a

^{2}) x (-2a

^{3})

= (-5) (-10) (-2) x a x a

^{2}x a

^{3}= -100a

^{1 + 2 + 3}= -100a

^{6}

**Question 11.**

**(-4x**

^{2}) x (-6xy^{2}) x (-3yz^{2})**Solution:**

(-4x

^{2}) x (-6xy

^{2}) x (-3yz

^{2})

= (-4) x (-6) x (-3) x

^{2}x x x y

^{2}x y xz

^{2}= -72x

^{2+1}x y

^{2+1}

*x*

_{z}

^{2}= 72x

^{3}y

^{3}z

^{3}

**Question 12.****Solution:**

**Question 13.****Solution:**

**Question 14.****Solution:**

**Question 15.****Solution:**

**Question 16.****Solution:**

**Question 17.**

**(2.3xy) x (0.1x) x (0.16)**

**Solution:**

(2.3xy) x (0.1x) x (0.16)

= 2.3 x 0.1 x 0.16 x x x x x y

= 0.0368x

^{1 +1}x y = 0.0368x

^{2}y

**Express each of the following products as a monomials and verify the result in each case for x = 1 : (18 -26)**

**Question 18.**

**(3x) x (4x) x (-5x)**

**Solution:**

**Question 19.****Solution:**

**Question 20.**

**(5x**

^{4}) x (x^{2})^{3}x (2x)^{2}**Solution:**

(5x

^{4}) x (x

^{2})

^{3}x (2x)

^{2}

= 5x

^{4}x x

^{2 x }

^{3}x 2x x 2x

= 5x

^{4}* x

^{6}x 4x

^{2}= 5 x 4 x x

^{4 + 6 + 2}= 20x

^{12}Verification:

L.H.S. = (5x

^{4}) x (x

^{2})

^{3}x (2x)

^{2}= 5 x (1)

^{4}x [(1)

^{2}]

^{3}x (2 x 1)

^{2}= 5 x 1 x (1)

^{2 x }

^{3}

_{x}(2)

^{2}= 5 x 1

^{6}x 2

^{2}= 5 x 1 x 4 = 20

R.H.S. = 20x

^{12}= 20 (1)

^{12}= 20 x 1 = 20

∴ L.H.S. = R.H.S.

**Question 21.(x ^{2})^{3} x (2x) x (-4x) x 5**

**Solution:**

(x

^{2})

^{3}x (2x) x (-4x) x (5)

= x

^{2 x}

^{3}X 2x X (-4x) X 5

= x

^{6}x 2x x (-4x) x 5 = 2 x (-4) x 5x

^{6+1 +1}

= -40x

^{8}Verification

L.H.S. = (x

^{2})

^{3}x (2x) x (-4x) x (5)

= (1

^{2})

^{3}x (2 x 1) x (-4 x 1) x 5

= 1

^{2 x 3 }x 2 x (- 4) x 5 = 1

^{6}x 2 x (-4) x 5

= 1 x 2 x (-4) x 5 = -40

R.H.S. = -40x

^{8}= -40 x (1)

^{8}

= -40 x 1 = -40

∴ L.H.S. = R.H.S.

**Question 22.Write down the product of -8x ^{2}y^{6} and – 20xy Verify the product for x = 2.5, y = 1.**

**Solution:**

Product of -8x

^{2}y

^{6}and -20xy

= (-8x

^{2}y

^{6}) x (-20xy)

= -8 x (-20) x

^{2}x

_{x}x y

^{6}x y = 160x

^{2 + 1}x y

^{6 + 1}= 160x

^{3}y

^{3}

Verification.

L.H.S. = (-8x

^{2}y

^{6}) x (-20xy)

= -8 x (2.5)

^{2}x (1) x (-20 x 2.5 x 1)

= -8 x 6.25 x 1 x -20 x 2.5

= (-50) x (-50) = 2500

R.H.S. = 160 x = 160 (2.5)

^{3}x (1)

^{7}= 160 x 15.625 x 1 =2500

∴ L.H.S. = R.H.S

**Question 23.**

**Evaluate : (3.2x**

^{6}y^{3}) x (2.1x^{2}y^{2}) when x = 1 and y = 0.5.**Solution:**

3.2x

^{6}y

^{3}x 2.1x

^{2}y

^{2}= 3.2 x 2.1 x x

^{6+2 }x y

^{3+2}

= 6.72x

^{8}y

^{5}= 6.72 x (1)

^{8}x (0.5)

^{5}= 6.72 x 1 x 0.03125

= 0.21

**Question 24.**

**Find the value of (5x**

^{6}) x (-1.5x^{2}y^{3}) x (-12xy^{2}) when x = 1, y = 0.5.**Solution:**

**Question 25.Evaluate : (2.3a ^{5}b^{2}) x (1.2a^{2}b^{2}) when a = 1, b = 0.5.**

**Solution:**

**Question 26.**

**Evaluate : (-8x**

^{2}y^{6}) x (-20xy) for x = 2.5 and y = 1.**Solution:**

**Express each of the following products as a monomials and verify the result for x = 1,y = 2: (27-31)**

**Question 27.**

**(-xy**

^{3}) x (yx^{3}) x (xy)**Solution:**

(-xy

^{3}) x (yx

^{3}) x (xy)

= -x x x

^{3 }x x x y

^{3 }x y x y = -x

^{1 }

^{+ }

^{3}

^{ + }

^{1}x y

^{3 + }

^{1}

^{ + }

^{1 }= -x

^{5}y

^{5}Verification:

L.H.S. = (-xy

^{3}) x (yx

^{3}) x (xy)

= (-1 x 2

^{3}) x [2 x (1)

^{3}] x (1 X 2)

= (-1 x 8) x (2 x 1) x (1 x 2)

= -8 x 2 x 2 = -32

R.H.S. =-x

^{5}y

^{5}= -(1)

^{5}(2)

^{5}= -1 x 32 =-32

∴ L.H.S. = R.H.S.

**Question 28.****Solution:**

**Question 29.****Solution:**

**Question 30.****Solution:**

**Question 31.****Solution:**

**Question 32.****Solution:**

**Question 33.****Solution:**

**All Chapter RD Sharma Solutions For Class 8 Maths**

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**All Subject NCERT Solutions For Class 8**

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