RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2


In this chapter, we provide RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 Maths pdf, free RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 Maths book pdf download. Now you will get step by step solution to each question.

TextbookNCERT
ClassClass 8
SubjectMaths
ChapterChapter 6
Chapter NameAlgebraic Expressions and Identities
ExerciseEx 6.2

RD Sharma Solutions for Class 8 Chapter 6 Algebraic Expressions and Identities Ex 6.2 Download PDF

Question 1.
Add the following algebraic expressions
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 1
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 2
Solution:
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 3
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 4
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Question 2.
Subtract:
(i) -5xy from 12xy
(ii) 2a2 from -7a2
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 7
Solution:
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 8
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RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 10
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Question 3.
Take away :
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 12
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 13
Solution:
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 14
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Question 4.
Subtract 3x – 4y – 7z from the sum of x – 3y + 2z and – 4X + 9y- 11z.
Solution:
Sum of x – 3y + 2z and – 4x + 9y – 11z
= x – 3y + 2z + (- 4x + 9y – 11z)
= x – 3y + 2z – 4x + 9y – 11z
= x – 4x – 3y + 9y + 2z – 11z
= – 3x + 6y – 9z
Now (-3x + 6y – 9z) – (3x – 4y – 7z)
= -3x + 6y – 9z – 3x + 4y + 7z
= -3x – 3x + 6y + 4y -9z +7z
= -6x + 10y – 2z

Question 5.
Subtract the sum of 3l- 4m – 7n2 and 2l + 3m – 4n2 from the sum of 9l + 2m – 3nand -3l + m + 4n2.

Solution:
Sum of 9l + 2m – 3n2 and -3l + m + 4n2
= 9l + 2m – 3 n2 + (-3l) + m + 4n2
= 9l + 2m – 3n2 – 3l + m + 4n2
= 9l- 3l+ 2m + m – 3 n2 + 4n2
= 6l + 3m + n2
and sum of 3l – 4m – 7n2 and 2l +3m- 4n2
= 3l- 4m – 7n2 + 2l+ 3m- 4n2
= 3l + 2l – 4m + 3m- 7n2 – 4n2
= 5l -m- 11n2
Now (6l + 3m + n2) – (5l – m – 11n2)
= 6l + 3m + n2 – 5l + m + 11n2
= 6l – 5l + 3m + m + n2 + 11n2
= l + 4m+ 12n2

Question 6.
Subtract the sum of 2x – x2 + 5 and -4x – 3 + 7x2 from 5.
Solution:
5 – (2x-x2 + 5-4x-3 + 7x2)
= 5 – (2x – 4x- x2 + 7x2 + 5-3)
= 5 – (-2x + 6x2 + 2)
= 5 + 2x – 6x2 – 2
= – 6x2+2x+3
= 3 + 2x – 6x2

Question 7.
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Solution:
RD Sharma Class 8 Solutions Chapter 6 Algebraic Expressions and Identities Ex 6.2 21
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