# RD Sharma Solutions Class 10 Chapter 7 Statistics Exercise 7.1

In this chapter, we provide RD Sharma Solutions for Class 10 Chapter 7 Statistics Exercise 7.1 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Solutions for Class 10 Chapter 7 Statistics Exercise 7.1 pdf, free RD Sharma Solutions for Class 10 Chapter 7 Statistics Exercise 7.1 book pdf download. Now you will get step by step solution to each question.

### RD Sharma Solutions Class 10 Chapter 7 Statistics Exercise 7.1

Question 1.
Calculate the mean for the following distribution :

Solution:

Question 2.
Find the mean of the following data:

Solution:

Question 3.
If the mean of the following data is 20.6. Find the value of p. (C.B.S.E. 1997)

Solution:

Question 4.
If the mean of the following data is 15, find p. (C.B.S.E. 1992C)

Solution:

Question 5.
Find the value of p for the following distribution whose mean is 16.6.

Solution:
Mean = 16.6

Question 6.
Find the missing value of p for the following distribution whose mean is 12.58. (C.B.S.E. 1992C)

Solution:

Question 7.
Find the missing frequency (p) for the following distribution whose mean is 7.68.

Solution:

Question 8.
The following table gives the number of boys of a particular age in a class of 40 students. Calculate the mean age of the students

Solution:

Question 9.
Candidates of four schools appear in a mathematics test. The data were as follows :

If the average score of the candidates of all the four schools is 66, find the number of candidates that appeared from school III.
Solution:

Question 10.
Five coins were simultaneously tossed 1000 times and at each toss the number of heads were observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.

Solution:

Question 11.
The arithmetic mean of the following data is 14, find the value of k. (C.B.S.E. 2002C)

Solution:
Mean=14

⇒ 14 (24 + k) = 360 + 10k
⇒ 336 + 14k = 360 + 10k
⇒ 14k- 10k- 360 -336 24
⇒ 4k = 24
⇒ k= (frac { 24 }{ 4 }) = 6 4
Hence k = 6

Question 12.
The arithmetic mean of the following data is 25, find the value of k. (C.B.S.E. 2001)

Solution:
Mean =25

⇒ 25 (14 + k) = 390 + 15k
⇒ 350 + 25k= 390 + 15k
⇒ 25k- 15k = 390 -350
⇒ 10k = 40 ⇒ k = (frac { 40 }{ 10 }) = 4
Hence k = 4

Question 13.
If the mean of the following data is 18.75. Find the value of p.

Solution:

⇒ 460 + 7p = 32 (18.75)
⇒ 460 + 7p = 600
⇒ 7p = 600 – 460 = 140
⇒ p =  (frac { 140 }{ 7 }) = 20
∴ p = 20

Question 14.
Find the value of p, if the mean of the following distribution is 20.

Solution:

⇒ 5p2 + 100p + 295 = 20 (15 + 5p)
⇒ 5p2 + 100p + 295 = 300 + 100p
⇒ 5p2 + 100p – 100p = 300 – 295
⇒  5p2 = 5 ⇒  p2  =  (frac { 5 }{ 5 })  = 1
⇒ P= ±1
P = -1 i s not possible
∴ p= 1

Question 15.
Find the missing frequencies in the following frequency distribution if it is known that the mean of the distribution is 50.

Solution:

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