RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2

In this chapter, we provide RD Sharma Solutions for Class 10 Chapter 15 Statistics Ex 15.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Solutions for Class 10 Chapter 15 Statistics Ex 15.2 pdf, free RD Sharma Solutions for Class 10 Chapter 15 Statistics Ex 15.2 book pdf download. Now you will get step by step solution to each question.

RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2

Question 1.
The. number of telephone calls received at an exchange per interval for 250 successive one-minute intervals are given in the following frequency table:
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 1
Compute the mean number of calls per interval.
Solution:
Let assumed mean (A) = 4
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 2
Hence mean number of calls per interval = 3.54

Question 2.
Five coins were simultaneously tossed 1000 times, and at each toss the number of heads was observed. The number of tosses during which 0, 1, 2, 3, 4, and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 3
Solution:
Let assumed means (A) = 3
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 4
Hence mean number of tosses per head = 2.47

Question 3.
The following table gives the number of branches and number of plants in the garden of a school.
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 5
Calculate the average number of branches per plant.
Solution:
Let assumed mean (A) = 4
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 6
∴Mean number of branches per plant = 3.62

Question 4.
The following table gives the number of children of 150 families in a village
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 7
Find the average number of children per family.
Solution:
Let assumed mean (A) = 3
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 8
= 3 – 0.65 = 2.35
Hence mean number of children per family = 2.35

Question 5.
The marks obtained out of 50, by 102 students in a Physics test are given in the frequency table below:
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 9
Find the average number of marks.
Solution:
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 10

Question 6.
The number of students absent in a class were recorded every day for 120 days and the
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 11
Solution:
Let assumed mean = 3
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 12
= 3 + 0.525 = 3.525 = 3.53 (approx)

Question 7.
In the first proof reading of a book containing 300 pages the following distribution of misprints was obtained:
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 13
Find the average number of misprints per page.
Solution:
Let assumed mean (A) = 2
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 14
= 2 – 127 = 0.73
∴ Average of number of misprints per page = 0.73

Question 8.
The following distribution gives the number of accidents met by 160 workers in a factory during a month.
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 15
Find the average number of accidents per worker.
Solution:
Let assumed mean = 2
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 16
= 2 – 1.168 = 2 – 1.17 = 0.83 (approx)
∴ Average number of accidents per worker = 0.83

Question 9.
Find the mean from the following frequency distribution of marks at a test in statistics
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 17
Solution:
Let assumed mean = 25
RD Sharma Class 10 Solutions Chapter 15 Statistics Ex 15.2 18
∴Average of marked obtained per student = 22.075

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