In this chapter, we provide RD Sharma Solutions for Class 10 Chapter 14 Co-Ordinate Geometry Exercise 14.1 for English medium students, Which will very helpful for every student in their exams. Students can download the latest RD Sharma Solutions for Class 10 Chapter 14 Co-Ordinate Geometry Exercise 14.1 pdf, free RD Sharma Solutions for Class 10 Chapter 14 Co-Ordinate Geometry Exercise 14.1 book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 14 |

Chapter Name | Co-Ordinate Geometry |

Exercise | 14.1 |

Category | RD Sharma Solutions |

**RD Sharma Solutions Class 10 Chapter 14 Co-Ordinate Geometry Exercise 14.1**

Question 1.

On which axis do the following points lie?

(i) P (5, 0)

(ii) Q (0 – 2)

(iii) R (-4, 0)

(iv) S (0, 5)

Solution:

(i) P (5, 0)

Its ordinate or y-axis is 0. It lies on x-axis

(ii) Q (0 – 2)

Its abscissa or x-axis is 0. It lies on y-axis

(iii) R (-4, 0)

Its ordinate is 0 It lies on x-axis

(iv) S (0, 5)

Its abscissa is 0. It lies on y-axis

Question 2.

Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when

(i) A coincides with the origin and AB and AD are along OX and OY respectively.

(ii) The centre of the square is at the-origin and coordinate axes are parallel to the sides AB and AD respectively.

Solution:

ABCD is a square whose side is 2a

(i) A coincides with origin (0, 0)

AB and AD are along OX and OY respectively

Co-ordinates of A are (0, 0), of B are (2a, 0) of C are (2a, 2a) and of D are (0, 2a)

(ii) The centre of the square is at the origin (0, 0) and co-ordinates axes are parallel to the sides AB and AD respectively.

Then the co-ordinates of A are (a, a) of B are (-a, a), of C are (-a, -a) and of D are (a, -a) as shown in the figure given below :

Question 3.

The base PQ of two equilateral triangles PQR and PQR’ with side 2a lies along y- axis such.that the mid-point of PQ is at the origin. Find the coordinates of the vertices R and R’ of the triangles.

Solution:

∆PQR and PQR’ are equilateral triangles with side 2a each and base PQ and mid of point of PQ is 0 (0, 0) and PQ lies along y-axis

RD Sharma Class 10th Solutions Chapter 14 Coordinate Geometry Ex 14.1 Q1

RD Sharma Class 10th Solutions Chapter 14 Coordinate Geometry Ex 14.1Q2

RD Sharma Class 10 Solutions Chapter 14 Coordinate Geometry Ex 14.1 Q3

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